Genetics

 

Hairless dog Hrhr - will survive

 Heterozygous Hairless Crested carries the dominant gene for hairlessness (Hr) and the gene for a normal coat (hr). A lethal gene (Hr) is dominant over the recessive (hr). Thus the Heterozygous Hairless is referred to as (Hrhr). 
Pic.© Katarzyna Zienkiewicz

Hrhr

Hairless dog HrHr - dies

 Homozygous Hairless Crested witch carries a double dose of the hairless gene (HrHr) will not survive.

Pic.© Katarzyna Zienkiewicz

 HrHr

Powder Puff

 The Powder Puff doesn't carry the hairless (Hr)gene, only the gene for coat (hr), thus the Powder Puff is referred to as (hrhr). This combination is not lethal.

Pic.© Katarzyna Zienkiewicz

 hrhr

Crossings:

Crossing - Hairless Hrhr x Hairless Hrhr

Pic.© Katarzyna Zienkiewicz

 The mating of two Hairless (HrHr) x (HrHr) would result in the following average combinations:

1 (HrHr) (25%) - Homozygous Hairless - Death, letal genes;
2 (Hrhr)  (50%) - Heterozygous Hairlesses - Will survive;
1 (hrhr)   (25%) - Homozygous Powder Puff - Will survive.
But this mating could produce all Hairlesses (Hrhr) or all Powder Puffs (hrhr) or any combination.

 

Crossing - Hairless Hrhr x Powder Puff hrhr

Pic.© Katarzyna Zienkiewicz

Mating a Hairless (Hrhr) to a Powder Puff (hrhr) would net the following avarage results:

2 (Hrhr)  (50%) - Heterozygous Hairlesses - Will survive;
2 (hrhr)   (50%) - Homozygous Powder Puffs - Will survive.
But this mating could produce all Hairlesses (Hrhr) or all Powder Puffs (hrhr) or any combination.

 

Crossing Powder Puff hrhr x Powder Puff hrhr

Pic.© Katarzyna Zienkiewicz

A Combination of  Powder Puff (hrhr) to a Powder Puff (hrhr) will have a result of:

4 (hrhr)   (100%) - Homozygous Powder Puffs - Will survive.

Sum up:

x hairless (Hrhr) powder puff (hrhr)
hairless (Hrhr) 1 hairless (HrHr) - dies

2 hairlesses (Hrhr)

1 powder puff (hrhr)

 2 hairlesses (Hrhr)

2 powder puffs (hrhr)
powder puff (hrhr)  

2 hairlesses (Hrhr)

2 powder puffs (hrhr)

 

 4 powder puffs (hrhr)

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